How to find the maximum velocity or accelreation? (1 Viewer)

Joined
Oct 29, 2011
Messages
872
Location
Narnia
Gender
Female
HSC
2013
E.g

v = v = 6t^2 + 3t -2

or

a = v = 6t^2 + 3t -2

i know for velocity and acceleration, it is the derivitive equal to zero.

but how do we prove that these points are a maximum? do we differentiate again, after already differentiating and sub values of t in?


++ Another question.

For displacement:

if d2y/dx2 = -2cos(pi/x)

is 7/6 or 11/6 a maximum point. thanks again. and why?
 

Shazer2

Member
Joined
Feb 16, 2012
Messages
439
Gender
Male
HSC
2013
For the first bit, you can either use first derivative and check gradient either side of the turning point, or you can use second derivative and check the concavity!
 

ocatal

Active Member
Joined
Sep 1, 2012
Messages
298
Gender
Male
HSC
2013
E.g

v = v = 6t^2 + 3t -2

or

a = v = 6t^2 + 3t -2

i know for velocity and acceleration, it is the derivitive equal to zero.

but how do we prove that these points are a maximum? do we differentiate again, after already differentiating and sub values of t in?


++ Another question.

For displacement:

if d2y/dx2 = -2cos(pi/x)

is 7/6 or 11/6 a maximum point. thanks again. and why?
You apply the same method to the function you're trying to find the maximum values of, regardless of it being the original function or not.
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top