how to integrate xsin^2x (1 Viewer)

[bos1234]

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[my answer]

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[MuffinMan]

the setting's right but when you have x^2/2-x^2/4, youre left with x^2/4 instead of x^2/2
just another one of those silly errors

 

[bos1234]

thanks for the help!

that was a bad mistake

 

[MAlame]

Hi....i know the integration of xsin^2x, but can u plz help me in finding the derivative of it....thnks alot

 

[MAlame]

thanks ..but ...sorryy i didnt make the ques clearer...i want to u to help me in finding sin^2x..plz....cuz im geting mixed up...do u change its form to linear and then do it..........

 

[watatank]

Hi....i know the integration of xsin^2x, but can u plz help me in finding the derivative of it....thnks alot

do you want d/dx[ sin²x]?

well think of it as (sinx)² and then use chain rule

= 2*sinx*cosx

alternatively you can use product rule

d/dx[ sin²x]

= d/dx[sinx * sinx]

= sinx*cosx + cosx sinx

= 2sinxcosx
is that what you were after?

 

[MAlame]

yep thnx .thats wat i was thinking of when i said to change it to the linear form..thnks for the help mate

 

[Mas112]

hey MAlame i was wondering if u can tell me the dervative of sin^2x and thnx

 

[watatank]

i) i answered it already.

ii) if these questions are serious and you actually need to know the answer, post in the mathematics forum not the 4u forum.

 

[Forbidden.]

i) i answered it already.

ii) if these questions are serious and you actually need to know the answer, post in the mathematics forum not the 4u forum.

I don't recall seeing integration of sin²x in any Mathematics textbooks or study guides, I only see them in Extension 1.

 

[*So WOnderful*]

hey MAlame i was wondering if u can tell me the dervative of sin^2x and thnx

sin^2(x) is the same as (sinx)^2
by function of a function rule, the derivative is:
2[sin(x)].cos(x)

 

[jemsta]

oh man if you cant differentiate sin^2x then you shouldnt be doing mathematics
also to integrate sin^2x, youll need the double angle formula, and only ext 1 students do double angles