hayabusaboston
Well-Known Member
Re: HSC 2013 3U Marathon Thread
From first glance dats what it looks like.
Consider (1+x)^n=nC0+nC1x+...nCnx^n, integrate twice, find ur C's, and let x=-1?Considering the identity:
Then expanding both sides, equate co-efficient of on both sides knowing that , the result comes immediately.
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From first glance dats what it looks like.