mahmoudali
Member
- Joined
- Aug 20, 2011
- Messages
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- HSC
- 2013
Re: HSC 2013 2U Marathon
![](https://latex.codecogs.com/png.latex?\bg_white \ \ $consider:$ 1 + \frac{1}{2} lnx + \frac{1}{4} (lnx)^2 + \frac{1}{8} (lnx)^3 +..... = \frac{2}{3} \ \ $find x$ )
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I think he wanted us to use limiting sum?Well I thought you'd let the sum of geometric series = 2/3, but I don't know number of terms or x. I got this far:
Yeah. If you give n, it's solvable I think.
yea lol there is no solution to the question you get ln(x) = -1, which is beyond even the 4U syllabusIs it wrong sai?
wat?yea lol there is no solution to the question you get ln(x) = -1, which is beyond even the 4U syllabus
I don't know what foreign mathematics you are going bywhat else would you use though
it writes +..... and i didnt write last term....
sy < me![]()
he's trying to troll its not workingwat?
so he wasnt trolling he failedwait
oh my god
wat?
yea lol there is no solution to the question you get ln(x) = -1, which is beyond even the 4U syllabus
So confused...Who to listen to =.=what else would you use though
it writes +..... and i didnt write last term....
sy < me![]()
lnx = -1 (no soln)dat fail
holy crap