No, i was referring to the integration of 1/xlnx because the person who attempted it used u-sub which is 3u
i think its just a 1 mark question, because 1/(xlnx) can be seen as (1/x)/(lnx), hence, ln(lnx)+c.How would you the first one using 2u method only?
Are you talking about f 1/xlnx ? If so, then I actually wouldn't have a clue if you could differentiate via 2u :/How would you the first one using 2u method only?
Dw. Hi im trash solved itAre you talking about f 1/xlnx ? If so, then I actually wouldn't have a clue if you could differentiate via 2u :/
Can you integrate two dx's in 2u?
Assuming it's 1 dx instead of two, it would eventually turn out like 1/x/lnx/ln (lnx) which integrated would be ln (ln (lnx))) + C. If it's two 2dx I'd have no clue
Lol i remember seeing that question in the Kings 4U paper, funny how it could actually be done with 2U technique.Question: View attachment 30783
I know this is possible with 2U knowledge, but I think these sort of questions are best left to the higher marathons, most students doing 2U anyway don't really want questions of that difficultyQuestion: View attachment 30783
I) it's a gp with r = -xQuestion: View attachment 30783
have already tried assuming k=1, ended up getting a result that was opposite in sign compared to II so ))))): saddayYeah, was a typo. It was meant to be k=1. Hint for (iv), use part (ii) and (iii).
Ah that explains everything thenSorry another typo . It's meant to be (-1)^(k+1)
also do you mean y=-10?Sorry. A better question: Find the volume of the solid of rotation when the region bounded by the curve y=(x-4)(8-x) and the lines x=4, x=8 and y=10 is rotated about the x-axis.