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HSC 2015 MX2 Integration Marathon (archive) (3 Viewers)

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Ekman

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Re: MX2 2015 Integration Marathon

Couldn't you have just let u^2 = x as the first step?
Or that, when I saw the question, rationalizing the denominator was the first thing that came to my mind, but of course your substitution is quicker.
 

Drsoccerball

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Re: MX2 2015 Integration Marathon

can we get some recurrence questions up in this b***h
 

Drsoccerball

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Re: MX2 2015 Integration Marathon

Is there a lot of algebra? At least I got the (b-a) part lol
Im thinking (because i love triangles) making two seperate triangle and finding expresions for the angles and then just using substitution and bam answer but ceebs
 

Ekman

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Re: MX2 2015 Integration Marathon

I got a final answer of
:p
I let u^2=b-x and had as a result:


Via triangles I got to the final integral:


After integrating, I expanded to get the final integrated version in my previous post
 
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Re: MX2 2015 Integration Marathon

found an algebra mistake and got [(b-a)(3sqrt3 - 6 - 3pi)]/12 lol
 
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Ekman

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Re: MX2 2015 Integration Marathon

Are you sure that the answer is:


Because I got:


The integrated version for me was:
Sorry guys, I just found my mistake.


Is correct. When I subbed in q, I forgot to square root it inside the arcsin term, so I got pi/6 rather than pi/4.
 

VBN2470

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Re: MX2 2015 Integration Marathon

NEW QUESTION:

 
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