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HSC Physics Marathon 2013-2015 Archive (3 Viewers)
- Thread starter Magical Kebab
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re: HSC Physics Marathon Archive
@indolence I've heard explanations of the Meissner effect with Lenz's Law but for HSC physics I don't think they want you to relate the two
For your question I would've included the following:
When a superconductor is cooled below its critical temperature it will experience zero electrical resistance do to the formation of Cooper Pairs (as predicted by the BCS theory) and the Meissner effect in which the magnet fields are expelled from the superconductor forcing the magnet to hover/levitate. It will remain hovering/levitating in the same position despite being pushed around due to the quantum pinning phenomena. However, this effect wears off when the superconductor rises above its critical temperature.
Should probably mention the terms diamagnetic and paramagnet somewhere in there as well
I haven't looked at I2I section 4 in a while so someone correct me if I'm wrong
It's also good to mention the exclusion of the magnetic field from the superconductor
@indolence I've heard explanations of the Meissner effect with Lenz's Law but for HSC physics I don't think they want you to relate the two
For your question I would've included the following:
When a superconductor is cooled below its critical temperature it will experience zero electrical resistance do to the formation of Cooper Pairs (as predicted by the BCS theory) and the Meissner effect in which the magnet fields are expelled from the superconductor forcing the magnet to hover/levitate. It will remain hovering/levitating in the same position despite being pushed around due to the quantum pinning phenomena. However, this effect wears off when the superconductor rises above its critical temperature.
Should probably mention the terms diamagnetic and paramagnet somewhere in there as well
I haven't looked at I2I section 4 in a while so someone correct me if I'm wrong
Physicklad
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re: HSC Physics Marathon Archive
if the answer is B, picture this: the moving stone gets to the bottom and then acceleration drops to zero. so the stone continues with a constant velocity after hitting the ground......???? dont make sense m8
so the graph must certainly extend below the t axis - but not for as long as shown in A
I would say A more than B although A is not perfect.... non of these answers are right. The real graph should look very similar to B, but it must extend below the t axis for at least a infinitesimal period of time. How would you get a moving stone to stop moving unless you apply a counterbalancing force?
help
if the answer is B, picture this: the moving stone gets to the bottom and then acceleration drops to zero. so the stone continues with a constant velocity after hitting the ground......???? dont make sense m8
so the graph must certainly extend below the t axis - but not for as long as shown in A
godofindolence
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re: HSC Physics Marathon Archive
Maybe the one in (B) actually went below the t-axis for a tiny amount, but too small for our eyes to see.
re: HSC Physics Marathon Archive
I think the graph is restricted to when it stops the moment the rock hits the water
+ InteGrand what's your (HSC level) understanding of the Meissner effect?
InteGrand being racist wot (lel jks)Maybe the one in (B) actually went below the t-axis for a tiny amount, but too small for our eyes to see.
I think the graph is restricted to when it stops the moment the rock hits the water
+ InteGrand what's your (HSC level) understanding of the Meissner effect?
re: HSC Physics Marathon Archive
For a true explanation, one must have a look at the London Equations: https://en.wikipedia.org/wiki/London_equations
Impossible to understand at HSC level. I'd just memorise whatever the TB says for that (like Jacaranda).
For a true explanation, one must have a look at the London Equations: https://en.wikipedia.org/wiki/London_equations
Kaido
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re: HSC Physics Marathon Archive
No transformers required to step up/down since little to no energy costs
Less coal is required to be burnt to produce the same amount of electricity thus further lowering the energy costs
The infrastructural cost will also include changing all power stations to DC since superconductors only work with DC (Cooper pairs cannot form under AC since the Cooper pairs only travel in one direction)
No transformers required to step up/down since little to no energy costs
Less coal is required to be burnt to produce the same amount of electricity thus further lowering the energy costs
Drsoccerball
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re: HSC Physics Marathon Archive
AC are affected by external magnetic fields (ceebs going into too much detail)
DC can use superconductors which allow for more efficient power transfer
DC doesn't lose energy like AC which uses it up in the form of eddy currents
Safer when closer to the user unlike AC which has 240V near the user
etc...
Devices use DC and therefore no change is required from power station to device.
AC are affected by external magnetic fields (ceebs going into too much detail)
DC can use superconductors which allow for more efficient power transfer
DC doesn't lose energy like AC which uses it up in the form of eddy currents
Safer when closer to the user unlike AC which has 240V near the user
etc...
re: HSC Physics Marathon Archive
Uy = Usin60
Use delta(x) = Ux*t in order to find t in terms of U
Then use delta(y) = Uy*t +1/2(ay)(t^2) and solve for U
Ux = Ucos60hgow do we do this:
Uy = Usin60
Use delta(x) = Ux*t in order to find t in terms of U
Then use delta(y) = Uy*t +1/2(ay)(t^2) and solve for U
turnerloos
TAFE Executive Officer
re: HSC Physics Marathon Archive
are we allowed use 3u method to solve physics projectile quesitons?
are we allowed use 3u method to solve physics projectile quesitons?
TQuadded
Breaking the limits.
re: HSC Physics Marathon Archive
I'm sure you'd lose marks just because you didn't use the Physics method, although you'll get some marks for having the right answer.
vitamin D
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