Prove by induction that: 31 + 32 + 33 + ... + 3n < 3n + 1 Thanks.
Dreamerish*~ Love Addict - Nakashima Joined Jan 16, 2005 Messages 3,705 Gender Female HSC 2005 Oct 4, 2005 #1 Prove by induction that: 31 + 32 + 33 + ... + 3n < 3n + 1 Thanks.
A acmilan I'll stab ya Joined May 24, 2004 Messages 3,989 Location Jumanji Gender Male HSC N/A Oct 4, 2005 #2 True for n = 1 Assume true for n = k 31 + 32 + 33 + ... + 3k < 3k+1 For n = k+1 31 + 32 + 33 + ... + 3k + 3k + 1 < 3k+1 + 3k+1 = 2.3k+1 < 3.3k+1 = 3k+1+1 = 3k+2 Hence 31 + 32 + 33 + ... + 3k + 3k+1 < 3k+2 and so forth...
True for n = 1 Assume true for n = k 31 + 32 + 33 + ... + 3k < 3k+1 For n = k+1 31 + 32 + 33 + ... + 3k + 3k + 1 < 3k+1 + 3k+1 = 2.3k+1 < 3.3k+1 = 3k+1+1 = 3k+2 Hence 31 + 32 + 33 + ... + 3k + 3k+1 < 3k+2 and so forth...
Dreamerish*~ Love Addict - Nakashima Joined Jan 16, 2005 Messages 3,705 Gender Female HSC 2005 Oct 4, 2005 #3 Gosh, that was fast. Thank you.