induction questions that are hard to do in tha wee hours of tha mornin (2 Viewers)

[KeypadSDM]

Originally posted by evilc
polynomial in x of degree (k-1)?

Yes, that's the best way of describing it.

 

[Grey Council]

the thing is, I've never seen anyone use those terms in Induction.

 

[KeypadSDM]

Originally posted by GuardiaN
the thing is, I've never seen anyone use those terms in Induction.

I was just clarifying what it was. If anything I was trying to make it more understandable. Oh the irony.

 

[ND]

I'll try and explain in case you still don't get it:

(x^k)-1=(x-1)[x^(k-1)+x^(k-2)+...+1]
So when you divide by (x-1), you get:
x^(k-1)+x^(k-2)+...+1

which is what keypad means by a polynomial in x with leading term x^(k-1)

 

[mazza_728]

so i said .. your car was upside down when i got here.

 

[Grey Council]

Originally posted by ND
I'll try and explain in case you still don't get it:

(x^k)-1=(x-1)[x^(k-1)+x^(k-2)+...+1]
So when you divide by (x-1), you get:
x^(k-1)+x^(k-2)+...+1

which is what keypad means by a polynomial in x with leading term x^(k-1)

Oh! I get it now. ta ND