Induction (1 Viewer)

[GUSSSSSSSSSSSSS]

Prove tan((pi/4)(2n+1))=(-1)^n

gah i keep getting tan(pi/2)'s in my answer
so it fuks it up lol

if anyone can help i thank you in advance lol XDDD

 

[tommykins]

Have you tried converting the tan(pi/2) into 1's ?

 

[Timothy.Siu]

Prove tan((pi/4)(2n+1))=(-1)^n

n=1
LHS=tan(3pi/4)=-1=RHS
therefore n=1 is true

assume true for some particular n=k, i.e.
tan((pi/4)(2k+1))=(-1)^k

Prove for n=k+1
i.e. tan((pi/4)(2k+3))=(-1)^(k+1)

RHS=-1^k x-1
LHS=-tan (pi-pi(2k+3)/4)=-tan(pi(1-(2k+3)/4)=-tan(pi/4(2k+1))

sub in n=k
LHS=(-1)^kx-1 =RHS

 

[GUSSSSSSSSSSSSS]

Prove tan((pi/4)(2n+1))=(-1)^n

n=1
LHS=tan(3pi/4)=-1=RHS
therefore n=1 is true

assume true for some particular n=k, i.e.
tan((pi/4)(2k+1))=(-1)^k

Prove for n=k+1
i.e. tan((pi/4)(2k+3))=(-1)^(k+1)

RHS=-1^k x-1
LHS=-tan (pi-pi(2k+3)/4)=-tan(pi(1-(2k+3)/4)=-tan(pi/4(2k+1))

sub in n=k
LHS=(-1)^kx-1 =RHS

sorry i cant quite read your notation lol sorry

but im finding it hard to follow as well
you seem to pull pi's outta nowhere sorry lol

 

[Timothy.Siu]

sorry i cant quite read your notation lol sorry

but im finding it hard to follow as well
you seem to pull pi's outta nowhere sorry lol

i used the fact that tan(180-x)=-tan x and factorised it

 

[GUSSSSSSSSSSSSS]

i used the fact that tan(180-x)=-tan x and factorised it

ohhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh ok
i keep missing those lol

i shall read it again and try and make sense of it lol


thanks

 

[lolokay]

+ all the other induction stuff

 

[tacogym27101990]

Have you tried converting the tan(pi/2) into 1's ?

lol

 

[Timothy.Siu]

lol

lol tan (pi/2) is imba man

 

[GUSSSSSSSSSSSSS]

ty everyone

 

[vds700]

Have you tried converting the tan(pi/2) into 1's ?

lol isnt tan(pi/2) undefined, and tan(pi/4) =1

 

[Timothy.Siu]

lol isnt tan(pi/2) undefined, and tan(pi/4) =1

obviously he was joking =P

 

[tommykins]

lol

lolz