Hey, started harder 3 unit last week, and i came across this quesiton in the arnolds text book.
Show that (b+c+d)(a+c+d)(a+b+d)(a+b+c) is greater than or equal to 81abcd
My teacher explained to me Cauchy's Theorem to solve this,
(a1+a2+a3+...an)/n is greater than or equal to (a1xa2xa3x...xan)^(1/n)
sorry bout the notation, so a1 represnts a number, or letter in this case, b,
and a2 represnts c and so on.
so (b+c+d) = (b+c+d)/3 is greater than or equal to (bcd)^1/3
and then u times it by the rest of them. my teacher wasnt to sure if i could use this theorem in the hsc, if not is there any other way to solve it?
Show that (b+c+d)(a+c+d)(a+b+d)(a+b+c) is greater than or equal to 81abcd
My teacher explained to me Cauchy's Theorem to solve this,
(a1+a2+a3+...an)/n is greater than or equal to (a1xa2xa3x...xan)^(1/n)
sorry bout the notation, so a1 represnts a number, or letter in this case, b,
and a2 represnts c and so on.
so (b+c+d) = (b+c+d)/3 is greater than or equal to (bcd)^1/3
and then u times it by the rest of them. my teacher wasnt to sure if i could use this theorem in the hsc, if not is there any other way to solve it?
Last edited by a moderator: