integrate for me? (1 Viewer)

[baby_pea]

hi,

can someone integrate ln squared for me please

thats really it.

 

[KFunk]

I assume you're talking about ∫ (lnx)²dx in which case use integration by parts where:

u = (lnx)² , u' = 2lnx/x
v'= 1 , v=x

∫ 1.(lnx)²dx

= x(lnx)² - 2∫ lnx dx (then use integration by parts again on lnx where u = lnx)

= x(lnx)² - 2( xlnx - 2∫dx)

= 2x - 2xlnx + x(lnx)² + C

 

[baby_pea]

you legend! gosh i hadn't even thought of using product rule

 

[baby_pea]

* chain rule

 

[Slidey]

You were right the first time - KFunk used a variation of product rule called integration by parts.