integration question from SBHS asssessment (1 Viewer)

vds700

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∫arcsinx/ sqrt(1+x) dx
0



solution is attached. I can't understand how they got from line 2 to line 3 ( the integral part). If someone could explain it, that'd be great.
 

Slidey

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Integration by parts.

Oh and sqrt(1+x)/sqrt(1-x^2) = sqrt(1+x)/sqrt((1-x)(1+x)), obviously.
 

vds700

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ah difference of squares, then u cancel the (1+x)...cant believe I didn't see it

Thanks Slidey!
 

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