integration question (1 Viewer)

Satiric

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Hey guys,

I need help with this integration question. This is from cambridge 2 unit btw.
Exercise 1D. Q21dii



i keep getting this

thanks in advance :D
 
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Trebla

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∫(x + 1)(x² + 2x)² dx = 1/2 ∫(2x + 2)(x² + 2x)² dx
= (x² + 2x)³ / 6 + c
since the derivative of x² + 2x is 2x + 2.
Alternatively, just expand it and integrate if you are unfamilar with reverse chain rule...
 

Satiric

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OMG...integration by sub
didn't think thats even in 2U
anyways thanks a lot guys :D
 

Trebla

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OMG...integration by sub
didn't think thats even in 2U
anyways thanks a lot guys :D
You were right that integration by substitution isn't in the 2 unit course. In a 2 unit context you would have to apply the reverse chain rule...usually you'll be asked to differentiate (x² + 2x)³ and then derive the integral from it at 2 unit level.
 

-Onlooker-

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OR you can just expand the expression, then simply differentiate.
 

xFusion

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If integration by sub is not in 2u, can you still use it in a 2u exam?
 

xFusion

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ok thats great because i cannot tell which of my work is 2 or 3u
 
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Ye, you just expand the equation on the right ( x)^2 , and then expand the equation on the left in. :rofl:
 

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