Integration reverse chain method (1 Viewer)

[Triage]

Not too sure. Can somebody please explain the reverse chain rule.

 

[asianese]

http://sydney.edu.au/stuserv/documents/maths_learning_centre/chainrulereverse.pdf

provides a good explanation.

 

[Triage]

I looked at that before and I couldn't follow it easily. I'm just getting confused with the use of the notation (dy/dx du/dx etc.)

 

[Triage]

Maybe example
Integral of 10x(5x^2 + 3) dx

 

[Combo]

i don't think you can use it without showing some working in 3u (showing d/dx in the integral), but i know it can be used without any working in 4u.

integral of 10x(5x^2+3)dx
= integral of d/dx(5x^2+3)*(5x^2+3)dx
= [(5x^2+3)^2]/2 + C

 

[Triage]

I learnt how to do it a couple of nights ago by rote. But thankyou very much itrungs, something you said just made it click and make actual sense to me.