Integration (1 Viewer)

[carbyheat]

Hey
I'm wondering if I could please get a hand with completing this integral...and it's pretty basic!
Int x.(1-x^2)^1/2 dx

Thanks very much in advance.

Carbyheat.

 

[pLuvia]

Int x(1-x²)^1/2dx
Let u=1-x²
du=-2xdx
-1/2Int u^1/2du
=-1/2[2/3u^3/2]+C
=-1/3(1-x²)^3/2+C

 

[carbyheat]

Cheers.

...I kept stuffing up the bounds. (which aren't in the i asked question- :mad1

 

[fireice]

u can also use trig sub
let x = sinx or cosx and itll be pretty good