Integration (1 Viewer)

[tommykins]

divide all terms by cos^2 x, have u tried that?

PS. doing from observation, cbf doing ti all.

 

[cutemouse]

Yeah I did that... But then when I let u=tanx, the upper limit is pi/2, which doesn't exist for tan.

So..?

 

[lolokay]

ha. maybe say that the integral gives the same value if the upper limit was (pi/2 - h) as h -> 0, h > 0 or something? i dono

edit: or break the initial integral into two integrals, one of which contains the 0 limit, and the other has the pi/2 limit. so then you can divide by cos^2x for the first one, and sin^2x for the second so you avoid both cot0 and tan(pi/2) ?

 

[cutemouse]

I figured it out... I had to take limits, this would be a nice 'novice separator' question in a trial lol...

 

[shaon0]

I=S (1-(sin(x)sqrt(1-(cos(x))^2)/(2-(cos(x))^2)) dx

This is half way through a solution.

 

[Iruka]

So your upper limit becomes infinity.

 

[Trebla]

Remember the inverse tan of infinity is pi/2...

 

[lolokay]

why not negative infinity, or -pi/2 for the inverse? (ie. isn't inverse tan not defined for pi/2? its range is -pi/2 < x < pi/2)

edit: though i guess you could say that since the function is always positive, it could only be pi/2

 

[Trebla]

Ok, if you want to get technical, then as x approaches infinity, tan^-1x approaches pi/2

 

[cutemouse]

Hi guys,

Seriously last question until next week ...



Tried letting and miserably failed

Thanks

 

[study-freak]

Which are now standard integrals.
Tell me if I did anything wrong.

 

[Ppen]

Just a question. How do u guys type in mathmatical notation (i.e the integrals)? Is there a program for it?

 

[tommykins]

latex editor

 

[Timothy.Siu]

Just a question. How do u guys type in mathmatical notation (i.e the integrals)? Is there a program for it?

latex?