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integration (1 Viewer)

Thread starter ashokkumar
Start date Jun 3, 2010

A

ashokkumar

Mr

#1

how would i integrate x*sqrt(1-4x)?

D

Drongoski

Well-Known Member

#2

$\int x\sqrt{1-4x}dx\ \ =\ \ -\frac{1}{4}\int (1-4x-1)\sqrt{1-4x}dx\\ \\ =\ \ -\frac{1}{4}\int (1-4x)^{^{\frac{3}{2}}}\ -\ (1-4x)^{\frac{1}{2}}\ dx\\ \\ =\ \ \frac{1}{4\times 4}\left [ \frac{2}{5}(1-4x)^{\frac{5}{2}} \ -\ \frac{2}{3}(1-4x)^{\frac{3}{2}}\right ]\ +\ C$

F

fullonoob

fail engrish? unpossible!

#3

drongoskis method is prob best, but you could also try integration by parts (which is messy)

omgmynameislong

Member

#4

Also try 1/4 sin^2 @

not sure if itll work i cbf.

seanieg89

Well-Known Member

#5

substituting u=1-4x yields answer with similar working to drogonski.

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