Integration! (1 Viewer)

kcqn93

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therefore y = x^2 + C

LOL

EDIT: ohh man LOL, thanks to the guy below! :)
 
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random-1006

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Therefore x = [log(2x)]/2 ??

The question that involved this



WTF is wrong with my example?
for your example to be correct , you are integrating (1/2x) with respect to y, NOT x !

TO GO FROM dx/dy= 1 / (2x) , you must integrate both sides with respect to y, NOT x

so its x= integral 1/ (2x) dy ( very important its dy), and i dont know you do that, think its some uni crap
 
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Tofuu

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But then how can you get a derivative of something in terms of itself? [2nd example]
not sure what you mean, but in the first example this is what you're doing



you cant integrate 1/2x if its dy


the second example is pretty much correct
 
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MetroMattums

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x^2, doesn't really answer my question
Notice how the dy is on the bottom? You can move it to the RHS of the equation and move the 2x on the otherside to the LHS and chuck integration operators in front to get an integration.
 

Tofuu

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You can do this


you cannot do this because its integrating in respect to y and yet you have x
 

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