Integration (1 Viewer)

yeyjasminetime · Oct 4, 2013

Could someone please explain 8 a)

Pleasepleaseplease?

HeroicPandas · Oct 4, 2013

$\frac{d}{dx}\left ( xlnx \right ) = lnx + 1$

Now integrate both sides with respect to x,

$\therefore \int \frac{d}{dx}\left ( xlnx \right ) = \int\left ( lnx + 1 \right )dx$
$\therefore \int \frac{d}{dx}\left ( xlnx \right ) = \int lnxdx + \int dx$

Make integral of lnx the subject,

$\int lnxdx = \int \frac{d}{dx}\left ( xlnx \right) - \int dx \\ \\ \int lnxdx = xlnx - x + C$

Note: If you differentiate something then integrate back its the same thing

yeyjasminetime · Oct 4, 2013

THANK YOU SO MUCH!!!
I really appreciate it ^^

Integration (1 Viewer)

yeyjasminetime

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HeroicPandas

Heroic!

yeyjasminetime

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