arctic-fox
New Member
- Joined
- Sep 2, 2015
- Messages
- 7
- Gender
- Female
- HSC
- 2016
Hey guys,
I need this cleared up. I understand it, but I'm not sure it's correct.
The other day it was explained to me by a teacher that none of the internal marks carry through - just the ranks. So for example...
Marks in Internal Assessment:
Person A) 95% (ranked 1st)
B)92 (2nd)
C)84 (3rd)
D)83 (4th)
E)79 (5th)
Then in the External Exam:
D)98
B)94
A)90
E)86
C)85
So my understanding is that Person D would get the 4th external exam mark (86) averaged with his real exam mark (98) to get 92 as a final result. None of the *marks* from internal assessments are counted, just the ranks when they're applied to the HSC exams. Each mark achieved in the HSC exam by a cohort goes to two people: the person who got that mark in the exam, and the person who ranked in that position in internal assessment. The two are averaged out as follows:
Person A) 98 (their rank applied to the HSC exam results) +90 (actual result) divided by 2 = 94
B) 92+94 / 2 = 93
C) 90+85 / 2 = 87.5
D) see above
E) 86+85 / 2 = 85.5
Does that make sense, and if so - is it correct????? It's the first time someone has explained it to me in a way I understand, but since everyone else (including other teachers) appears just as confused as I am, I'm not entirely sure it's correct.
Can someone confirm/deny this? I'm about to start trials and I think it's about time I knew for sure what was going on with internal assessment.
Thank you!
I need this cleared up. I understand it, but I'm not sure it's correct.
The other day it was explained to me by a teacher that none of the internal marks carry through - just the ranks. So for example...
Marks in Internal Assessment:
Person A) 95% (ranked 1st)
B)92 (2nd)
C)84 (3rd)
D)83 (4th)
E)79 (5th)
Then in the External Exam:
D)98
B)94
A)90
E)86
C)85
So my understanding is that Person D would get the 4th external exam mark (86) averaged with his real exam mark (98) to get 92 as a final result. None of the *marks* from internal assessments are counted, just the ranks when they're applied to the HSC exams. Each mark achieved in the HSC exam by a cohort goes to two people: the person who got that mark in the exam, and the person who ranked in that position in internal assessment. The two are averaged out as follows:
Person A) 98 (their rank applied to the HSC exam results) +90 (actual result) divided by 2 = 94
B) 92+94 / 2 = 93
C) 90+85 / 2 = 87.5
D) see above
E) 86+85 / 2 = 85.5
Does that make sense, and if so - is it correct????? It's the first time someone has explained it to me in a way I understand, but since everyone else (including other teachers) appears just as confused as I am, I'm not entirely sure it's correct.
Can someone confirm/deny this? I'm about to start trials and I think it's about time I knew for sure what was going on with internal assessment.
Thank you!