You could also get the same answer with this differentiation, if you figured out what cos (sin^{-1} x) was without resorting to trigonometric functions. Note:collide said:Hi, can someone please help me find the derivative of:
y=sin(sin inverse x)
I did:
dy/dx = 1/sq rt.(1-x^2) cos (sin inverse x)
Apparently the answer is 1 according to the textbook.
Thanks!
That was really helpful. Thanks.SoulSearcher said:You could also get the same answer with this differentiation, if you figured out what cos (sin^{-1} x) was without resorting to trigonometric functions. Note:
sin (sin^{-1} x)
Let @ = sin^{-1} x
Therefore x = sin @
Drawing the triangle, you find that cos @ = rt(1-x^{2})
But @ = sin^{-1} x, therefore cos @ = cos (sin^{-1} x) = rt(1-x^{2})