inverse trig. (1 Viewer)

[joesmith1975]

cant figure it out

 

[XcarvengerX]

what can't you figure out?

 

[insert-username]

You've actually been doing inverse trig for a while - every time you enter [SHIFT] [SIN] 0.5 = 30 on your calculator, in fact, and every other time you've used your calculator to find an angle. The 3 unit chapter simply expands it to graphing and calculus. Just remember: the inverse trig function is an angle.


I_F

 

[joesmith1975]

i dont why the .doc file didnt come up got it now please help

 

[word.]

Look on your integral sheet if you forgot that d(ArcSin{x})/dx = 1/Sqrt{1 - x²}; then it's just basic differentiation...

y = x*ArcSin{x} + Sqrt{1 - x²}
y' = x*(1/Sqrt{1 - x²}) + ArcSin{x} - 2x/(2Sqrt{1 - x²}) = ArcSin{x}