Inverse trig (1 Viewer)

Carrotsticks · May 17, 2012

Aysce said:
Question:

Find the domain of y=arcsin(x^2)

$\\ -1 \leq x^2 \leq 1 \\\\ $But we know that $ x^2 \geq 0 $ for all real $ x $ so we can change this inequality to make it $ 0 \leq x^2 \leq 1 \\\\ $We can look at these inequalities separately if you like:$ \\\\ x^2 \geq 0 $ for all real $ x $ so we can 'ignore' this one since it's trivial. $ \\\\ $So we look at the other part, which is $ x^2 \leq 1 \\\\ -1 \leq x \leq 1 \\\\ $And so that is our answer.$$

RishBonjour · May 18, 2012

You must spread some Reputation around before giving it to Carrotsticks again.

I was confused about the same problem.

Carrotsticks's explanation/working out seems to be the easiest to understand!

Sanjeet · May 19, 2012

SpiralFlex said:
Why you laugh at Spiral?

Your last comment lol

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Inverse trig (1 Viewer)

Carrotsticks

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RishBonjour

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Sanjeet

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