Inverse Trig (1 Viewer)

[Kutay]

Hey everyone i was wondering how you would answer this question, i have just started this topic and wondering for a bit of help!

"Without Caculators or tables evaluate the following:"

sin to -1 ( sin pi/3)

 

[KFunk]

It should just be π/3 since sin^-1 undoes sin. Hence sin^-1(sinπ/3) = π/3

EDIT: I thought I should clarify that there are exceptions to sin^-1(sinx) = x. eg sin^-1(sinπ ) ≠ π. It in fact equals zero (since inverse sin of zero is zero) so look out for when x = nπ and n= 0, ±1 ±2 etc...

 

[Trev]

I'm not too sure, we did this ages ago, but;
sin^-1[sin.pi/3] = pi/3; as there is the same sine ratio in a sine angle or something, I'm not too sure how to explain it

 

[FinalFantasy]

I'm not too sure, we did this ages ago, but;
sin^-1[sin.pi/3] = pi/3; as there is the same sine ratio in a sine angle or something, I'm not too sure how to explain it

i think sin^-1 x is the same as "the angle who's sin is x"
so sin^-1[sin.pi/3] would be "the angle who's sin is sin pi\3"
and that's pi\3

 

[Trev]

i think sin^-1 x is the same as "the angle who's sin is x"
so sin^-1[sin.pi/3] would be "the angle who's sin is sin pi\3"
and that's pi\3

Well I can't explain... I just do! lol

 

[FinalFantasy]

Well I can't explain... I just do! lol

hehe(dis stupid 10 letters thing is very annoying)

 

[mulley_773]

Just go:

sin^-1 (sin pi/3)
= sin^-1 (root 3)/2
= pi/3