• Congratulations to the Class of 2024 on your results!
    Let us know how you went here
    Got a question about your uni preferences? Ask us here

Limits (infinity) (1 Viewer)

aussiechica

Member
Joined
Jul 11, 2003
Messages
127
how do you solve limits as they approach infinity?
Ive tried 2 diff texts and neither of them are helpful

So any help here is appreciated Thanks!
 

sukiyaki

emptiness
Joined
Nov 9, 2002
Messages
1,505
Location
westie
Gender
Female
HSC
2003
what i always do is plug in a huge number and if its negative i plug in a smallish number

and then you seen what it kinda is close to
lets say
as x--> infinity in "7 / x + 2"
7 / (very big number)

it almost equal to zero but it 0+ (tiny bit bigger then zero)
 

wogboy

Terminator
Joined
Sep 2, 2002
Messages
653
Location
Sydney
Gender
Male
HSC
2002
Also when you need to sub in x=infinity into the expression to calculate the limit, always make sure that x is only in the denominator:

e.g. find lim (x->infinity) (x^2 - 2x + 2)/(3x^2 - x + 1)

{simply divide top & bottom of that fraction by x^2}
= lim (x->infinity) (1 - 2/x +2/x^2)/(3 - 1/x +1/x^2)

As a rule, anything divided by infinity (except infinity itself) is equal to zero. Also note that infinity = infinity^2 = infinity^1000 (infinity to the power of any positive number)

= (1 - 2/infinity + 2/infinity^2)/(3 - 1/infinity + 1/infinity^2)
= 1/3

If the function of x grows indefinitely (i.e. you can't put x into the denominator) then just say that "the limit doesn't exist"

e.g. lim (x->infinity) x^2
You can't simply put this into the form of a number divided by x like the previous question, so the limit doesn't exist.
 
Last edited:

Winston

Active Member
Joined
Aug 30, 2002
Messages
6,128
Gender
Undisclosed
HSC
2003
ok all u need to know is that


the first thing u do is

look for the highest power



example question



x^4 - 1
----------

x^2 - x


x -> infinity



so in this case the highest power is x^4


you divide the whole numerator and denominator by x^4


so

x^4 1
----- - -------
x^4 x^4

------------------


x^2 x
------ - -------
x^4 x^4



= 1 - 1/ x^4
--------------
1/x^2 - 1/x^3


so as x -> infinity

then the answer is


= 1


u just eliminate all th ones with the x's in them


so yeah simple enough
 

Dangar

Member
Joined
Apr 18, 2003
Messages
125
Location
Sydney
ok i can follow wogboy's example, but i get stuck on yours Winston when you get to

1 - 1/ x^4
-------------
1/ x^2 - 1/ x^3


so then you say just cancel everything divided by x because it will equal zero. But then wouldn't you be left with 1 / 0 which you just can't do?
 

wogboy

Terminator
Joined
Sep 2, 2002
Messages
653
Location
Sydney
Gender
Male
HSC
2002
But then wouldn't you be left with 1 / 0 which you just can't do?
If you get an answer of 1/0 (or infinity) it means the limit does not exist, and this is what you write as your answer. This means the answer to Winston's limit is that "the limit doesn't exist".

If on the other hand you get an answer of 0/0 (or infinity/infinity) it means you haven't simplified the limit properly yet (i.e. you haven't put x in the denominator only). Try again.

so remember this:

1/0 (or infinity, or any non-zero number divided by zero) = The limit doesn't exist, but you've still done it properly.

0/0 (or infinity/infinity) = You've done a mistake, or haven't completely done the question. Try again.

Any other result (e.g. 1/2) = This is the answer, you've done it properly.
 
Last edited:

Winston

Active Member
Joined
Aug 30, 2002
Messages
6,128
Gender
Undisclosed
HSC
2003
sorry my bad lol it wasnt much of a good example i made up
if u guys give me one out of ur textbook i can explain it through easily
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top