Locus/Parabola (1 Viewer)

[jyu]

Find the expression for the distance PA is A is the point (-3,4) and P is any point (x,y).
show that the locus of the point P which moves so that the distance PM from the axis is equal to its distance PA from the point (-3,4) is 8y=x^2+6x+25

which axis? x or y?

It is the x-axis because the parabola is a quadratic function of x.

If the quadratic function were not given, there would be two possibilities,
one from the x-axis: 8y=x^2+6x+25,
and the other from the y-axis: -6x=y^2-8y+25

:wave: