locus question (1 Viewer)

[Schniz]

sketch the graph x=y^2 marking its focus on the graph.

i am sure this is easy but i cant work out how to find the focus.

thanks.

 

[Mountain.Dew]

sketch the graph x=y^2 marking its focus on the graph.

i am sure this is easy but i cant work out how to find the focus.

thanks.

y^2 = 4ax, where 4a = 1 , a = 1/4

SO, its a normal parabola, except that its rotated 90 degrees clockwise, and the focus is (1/4, 0), directrix is x=-1/4, vertex remains at (0,0).

hope it helps, M.D.