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Lemiixem

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If log2 = 0.6 and log3 = 1.2 find:
(c) log1.5b^2

All logs have base b
 
C

Cl324

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log 3 - log 2 = 1og 1.5 = .6
log1.5b^2 = log 1.5 + log b^2 = .6+ 2logb =.6 +2 =2.6
 
mahli

mahli

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Sup!
All base b.
log(1.5b^2)
= log(b^2) + log(1.5)
= 2log(b) + log(3) - log(2)
= 2(1) + 1.2 - 0.6
= 2.6
 
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