B brahmin New Member Joined Apr 21, 2010 Messages 3 Gender Male HSC N/A Apr 21, 2010 #1 Can anyone do this?? We know that 2^10 = 1024 so that 2^10 can be represented as a 4 digit numeral. How many digits are there in 2^1000 when written as a numeral?
Can anyone do this?? We know that 2^10 = 1024 so that 2^10 can be represented as a 4 digit numeral. How many digits are there in 2^1000 when written as a numeral?
ohexploitable hey Joined Dec 31, 2009 Messages 4,741 Location sarajevo Gender Female HSC 2015 Uni Grad 2017 Apr 21, 2010 #2 Just stick it in your calculator? I got 31 digits.
B brahmin New Member Joined Apr 21, 2010 Messages 3 Gender Male HSC N/A Apr 21, 2010 #3 hmmm think ur meant to work it out though apparently its only a one mark question too so either theres a really easy method im just not seeing, or its worded wrong
hmmm think ur meant to work it out though apparently its only a one mark question too so either theres a really easy method im just not seeing, or its worded wrong
ohexploitable hey Joined Dec 31, 2009 Messages 4,741 Location sarajevo Gender Female HSC 2015 Uni Grad 2017 Apr 21, 2010 #4 If it's one mark then you just write "31".
B brahmin New Member Joined Apr 21, 2010 Messages 3 Gender Male HSC N/A Apr 21, 2010 #5 yeh but my calculator cant work it out ive got one of the older casios
NewiJapper Active Member Joined Jul 19, 2009 Messages 1,010 Location Newcastle Gender Male HSC 2010 Apr 21, 2010 #6 get a better one then...
D Drongoski Well-Known Member Joined Feb 22, 2009 Messages 4,254 Gender Male HSC N/A Apr 21, 2010 #7 brahmin said: Can anyone do this?? We know that 2^10 = 1024 so that 2^10 can be represented as a 4 digit numeral. How many digits are there in 2^1000 when written as a numeral? Click to expand... I did a similar one last year. It is equal to log10 21000 = [1000 log10 2] + 1 = [1000 x 0.30102999 . . .] = 301 + 1 = the nearest whole no + 1 = 302 Edit Corrected as above Last edited: Apr 21, 2010
brahmin said: Can anyone do this?? We know that 2^10 = 1024 so that 2^10 can be represented as a 4 digit numeral. How many digits are there in 2^1000 when written as a numeral? Click to expand... I did a similar one last year. It is equal to log10 21000 = [1000 log10 2] + 1 = [1000 x 0.30102999 . . .] = 301 + 1 = the nearest whole no + 1 = 302 Edit Corrected as above
D Drongoski Well-Known Member Joined Feb 22, 2009 Messages 4,254 Gender Male HSC N/A Apr 21, 2010 #8 Dragonmaster Last edited: Apr 22, 2010
N nonsenseTM Member Joined May 29, 2009 Messages 151 Gender Male HSC 2010 Apr 21, 2010 #9 isn't it 302 cos the log thing shows 10^(1000 x 0.30102999 . . .)=2^1000=10^(301.0299) which has 302 digits , ie 10^1.1 is a 2 digit no.
isn't it 302 cos the log thing shows 10^(1000 x 0.30102999 . . .)=2^1000=10^(301.0299) which has 302 digits , ie 10^1.1 is a 2 digit no.
C cutemouse Account Closed Joined Apr 23, 2007 Messages 2,250 Gender Undisclosed HSC N/A Apr 21, 2010 #10 This is from the 2U 2003 or 2005 HSC (IIRC). The answer is 302. You need to establish a pattern for this type of question.
This is from the 2U 2003 or 2005 HSC (IIRC). The answer is 302. You need to establish a pattern for this type of question.