Math 3U Hard Qn bank (2 Viewers)

[Average Boreduser]

I was thinking we could all maybe post questions we've found hard as the hscs r coming in pretty quick. I'll start us off w


Took me a fair while to pull it out smh

 

[alewe]

SBHS 22

 

[Average Boreduser]

 

[Test-king12]

 

[Average Boreduser]

 

[bruhmoment.]

cba to screenshot from thsc. But the 2022 NSB paper is on the harder side in general, esp Q14. Maybe the last question of NSB 2023 asw.

 

[Average Boreduser]

cba to screenshot from thsc. But the 2022 NSB paper is on the harder side in general, esp Q14. Maybe the last question of NSB 2023 asw.

tbh the qn be4 that was way weirder lmao. Treky but weird iycmd

 

[bruhmoment.]

tbh the qn be4 that was way weirder lmao. Treky but weird iycmd

the projectile q for 2023? nah it was much better than 2022 tho, at least I knew exactly what to do and what they were asking for, 2022 was like erm what the sigma.

 

[penguinzombie]

I was thinking we could all maybe post questions we've found hard as the hscs r coming in pretty quick. I'll start us off w

View attachment 44175
Took me a fair while to pull it out smh

i think im an idiot, how are u even meant to start this, doesnt the golfball hit the ground before 21 seconds anyway

 

[Average Boreduser]

i think im an idiot, how are u even meant to start this, doesnt the golfball hit the ground before 21 seconds anyway

No not the case. A projectile can theoretically go for as long as u want to assuming u get the initial trajectories sufficient conditions. How you should do this though is derive the formula for the object that collides with the golf ball. and then substitute the t-5 (since it starts after the golf ball already projected) since you know that d(t-5)/dt=1 (hence doesn't affect the integrations). for there equate y and u got ur answer boss man.

 

[penguinzombie]

No not the case. A projectile can theoretically go for as long as u want to assuming u get the initial trajectories sufficient conditions. How you should do this though is derive the formula for the object that collides with the golf ball. and then substitute the t-5 (since it starts after the golf ball already projected) since you know that d(t-5)/dt=1 (hence doesn't affect the integrations). for there equate y and u got ur answer boss man.

yeah i saw another post on this question and realised I was being dumb thank you