MATH1901 Assignment (1 Viewer)

[withoutaface]

For the second image you can actually derive the formula of the new curve in terms of x and y quite easily if you let z=x+iy.

Otherwise, plot more points like Xayma said.

I found it was easier using polar coordinates...

 

[Templar]

I found it was easier using polar coordinates...

First image, yes.

Second image, if you use x+iy, you can get the formula for the image of the lines PQ and QR. For RP polar is easier.

 

[antarctic]

Another way of doing it is dividing triangle PQR into the lines PQ, PR and QR.. and expressing them in terms of z = x + iy, and placing restrictions on x and y.

Good luck

Antarctic

 

[gordo]

still got nfi
fuk maths

 

[gordo]

can someone1 pm and help me plz?

 

[Trev]

can someone1 pm and help me plz?

lol...... what mark did you get in ext1/ext2 maths again?
Does everyone turn stupid when they get to uni! jks lol

 

[gordo]

lol i can't remember anything from the hsc
and the lectures are at 8am so i miss half

i can do all of question 1 and 2
i just don't understand this drawing thing

i tried splitting up into QP QR and RP
finding the point say Q which is -1+i
subbing it into w=e^iz
and u get like 1/e^(1+i)

htf do u plot that?

wen i don't ceonceptually understand something, i just have no chance
wtf is going on wen u are changin that triangle and turning all the points in e^iz

 

[Plebeian]

Use the fact that

e^z = e^x+iy = e^xcis(y)

 

[gordo]

so e^iz = e^-ycisx

how can u use the x coordinate from z plane and just turn it into the arg considering the x coord might be like 1 or -1/2

 

[gordo]

ended up handind with an obviously wrong but unfixable question 3

 

[xiao1985]

really asmt shouldn't all be that hard...
the real stress shud be in quiz + exam...
if u'd have 100% confience in asmt, u'd at least get 80%...

 

[gordo]

the maths is just beyond the lvl i am prepared to function at