Mathematics solutions (1 Viewer)

perpetuity · Oct 24, 2011

cheschirecat said:
They're asking for the value of the integral not the area so in this case it would be negative.

ur a newbs

perpetuity · Oct 24, 2011

jamesfirst said:
this is what I got.

wow, you got something right for once u dumb shit!

jamesfirst · Oct 24, 2011

cheschirecat said:
Fixed 1a) I'm an idiot for doing that -.- haha
3aii) a=3000000 n=110 d=500000
$Cost=\frac{110}{2}(2\times 3000000+119\times 500000)$
=3602500000

hmm for 10 aii) you're probably right, I'm tempted to think it would be 90 though since they're asking for the maximum value which wouldn't be 89 either, so I'd assume you'd just round it off to the nearest point not just downwards, I'll put both results in though.

holy shit. I didn't actually put it in millions.

I actually used the value 5 and stuff.... does that matter??!?!?!!

cheschirecat · Oct 24, 2011

perpetuity said:
HAHAHAHHAHAHA... i'm loving the fact that james first keeps saying he got things wrong.

ALSO, LOL @ OP. COuldn't even the get the very first question correct, rounding to correct number of sig figs or decimal places correct. Man, you are dumb. Who is going to trust the rest of your answers after that display of fail? I could easily put up 100% gauranteed correct solutions in less than 1hr, but the dumb fucks keep banning me.

Haha you're right it was stupid and I'm not claiming all my answers are right that's why I'm asking people to check

jamesfirst · Oct 24, 2011

cheschirecat said:
they're asking for the value of the integral not the area so in this case it would be negative.

fark!!!!!!!

perpetuity · Oct 24, 2011

jamesfirst said:
holy shit. I didn't actually put it in millions.

I actually used the value 5 and stuff.... does that matter??!?!?!!

HAHAH another fail by jamesfirst.

cheschirecat · Oct 24, 2011

sinsolja said:
Yep i got that in the exam.

You're right I'm an idiot what with saying n was 119 just did most of it in my head and I'm not really awake so I'm making stupid mistakes left and right

thanks for correcting this.

o_0 · Oct 24, 2011

sinsolja said:
4 e)
$y\leq 4 -x^{2}$
And
$y\geq \left | X \right |-2$

YESS, time for celebratory smoke. saved my heart there sinsolja

sinsolja · Oct 24, 2011

cheschirecat said:
You're right I'm an idiot what with saying n was 119 just did most of it in my head and I'm not really awake so I'm making stupid mistakes left and right thanks for correcting this.

I done the exact same mistake in the exam. Expect i corrected my self when i was looking back during checking time.

forkandspoon · Oct 24, 2011

Yeah. Thanks heaps for this. Btw, i think question 5 a iii has been rounded off wrong. i think it is 552.8.. do you agree?

sinsolja · Oct 24, 2011

o_0 said:
YESS, time for celebratory smoke. saved my heart there sinsolja

Ahahaha, yeh it scared me as well , but i looked over the question and the answer i posted is correct :S
enjoy your smoke

cheschirecat · Oct 24, 2011

sinsolja said:
I done the exact same mistake in the exam. Expect i corrected my self when i was looking back during checking time.

Hmm hopefully I just made the mistake now and not during the exam

Awkward_Ninja · Oct 24, 2011

asianese said:
3aii) Should be $3,327,500,000 I think...

That's what i got.

Screwed 2e, 3e, 5b, 6b, 6ci,v, 8bii, 8cii2, 9di, 10bii-v.

Oh well. Can't change it now.

perpetuity · Oct 24, 2011

Just so everyone knows.

Tommorow, unsw library 2pm. I am going to be helping 2011 HSC 2unit maths students (lolololol)

HAHAHA

o_0 · Oct 24, 2011

cheschirecat said:
Fixed 1a) I'm an idiot for doing that -.- haha
3aii) a=3000000 n=110 d=500000
$Cost=\frac{110}{2}(2\times 3000000+>>>109<<<\times 500000)$
=3602500000

hmm for 10 aii) you're probably right, I'm tempted to think it would be 90 though since they're asking for the maximum value which wouldn't be 89 either, so I'd assume you'd just round it off to the nearest point not just downwards, I'll put both results in though.

its meant to be 109 not 119...

edit: oo sorry i didnt see ur post after !

perpetuity · Oct 24, 2011

Awkward_Ninja said:
That's what i got.

Screwed 2e, 3e, 5b, 6b, 6ci,v, 8bii, 8cii2, 9di, 10bii-v.

Oh well. Can't change it now.

That';s some massive fail son, say goodbye to decent mark. You will get something shit like 70% (maybe)

cheschirecat · Oct 24, 2011

sinsolja said:
Ahahaha, yeh it scared me as well , but i looked over the question and the answer i posted is correct :S
enjoy your smoke

I think both are correct, abs(x)-2<=4-x^2 - Wolfram|Alpha seems to point towards it but I will add this answer too.

Mjontrix · Oct 24, 2011

could you move the y over so it would be be alrger/less than 0?

Awkward_Ninja · Oct 24, 2011

perpetuity said:
That';s some massive fail son, say goodbye to decent mark. You will get something shit like 70% (maybe)

Wow you don't need to be so condescending.
For the ones that were 2 or more marks, i may have got 1 or 2.
90/120 isn't that bad, is it?

OmmU · Oct 24, 2011

This builds my confidence

EDIT: for the graph I had the region as:

$|x|-2\leq y \leq 4-x^2$
$-2 \leq x \leq 2$

Mathematics solutions (1 Viewer)

Banned

Banned

Active Member

Premium Member

Active Member

Banned

Premium Member

Member

Member

New Member

Member

Premium Member

Member

Banned

Member

Banned

Premium Member

Premium Member

Member

★ BoS Deity ★

Users Who Are Viewing This Thread (Users: 0, Guests: 1)