Mathematics Thread (2 Viewers)

[Flatuitous]

its from ngo and sons, its from the topic 3u diffrential equations

wait why is it in differential?

 

[CirrusTheJet]

Sorry for the ambiguity. I was referring to the tangent question with the curve that we had to find.


The problem I posted isn't really that hard. Just simple trigonometry and simplifying.

 

[Flatuitous]

Sorry for the ambiguity. I was referring to the tangent question with the curve that we had to find.


The problem I posted isn't really that hard. Just simple trigonometry and simplifying.

oh oops

 

[Flatuitous]

Sorry for the ambiguity. I was referring to the tangent question with the curve that we had to find.


The problem I posted isn't really that hard. Just simple trigonometry and simplifying.

could you send the question here? I'm curious

 

[CirrusTheJet]

anyone wanna give this question a go?, idk how to solve it properly,
Question: Consider a curve in the first quadrants. The tangent at any point P cuts the x-axis at Q. Given that OP=PQ, where O is the origin, and that the point (1,4) lies on the curve, find the equation of the curve

 

[Jaros]

Sorry for the ambiguity. I was referring to the tangent question with the curve that we had to find.


The problem I posted isn't really that hard. Just simple trigonometry and simplifying.

Cirrus if ud like I can post some really hard 3u projectile or U can check out the HSC for 3u they always have a decent projectile question every year

 

[Flatuitous]

anyone wanna give this question a go?, idk how to solve it properly,
Question: Consider a curve in the first quadrants. The tangent at any point P cuts the x-axis at Q. Given that OP=PQ, where O is the origin, and that the point (1,4) lies on the curve, find the equation of the curve

wait OP can't be PQ unless you mean |OP|=|PQ|

edit:
well OP *can* be PQ but that implies that P also lies on the x axis which i doubt is what we're meant to consider since the *curve* is in the first quadrant while the x axis doesn't lie in any quadrant

 

[Jaros]

yeah I meant |OP|=|PQ|

 

[ineed99atar]

any help? ik its easy but tm brain is fried

 

[Jaros]

here working out:

U go to ngo and sons aswell, peak recognises peak

 

[Jaros]

for the LHS bit where I equate coefficients to like 1 and 0, its by comparing coefficients from LHS to RHS, and the answer is 1 because there are an odd number of terms so 1 'a0' remains or else if it was even number of terms they would all cancel out and by notice pattern I mean see how a1,a2,a3,a4 are all either -a0 or +a0

 

[Jaros]

Edit also for the last term x^n it should have been (an-1 +an)x^n sorry for the rushed mistake

 

[Dzeeshr]

wait OP can't be PQ unless you mean |OP|=|PQ|

edit:
well OP *can* be PQ but that implies that P also lies on the x axis which i doubt is what we're meant to consider since the *curve* is in the first quadrant while the x axis doesn't lie in any quadrant

You don’t need this when the question is obviously not dealing with vectors, but distances/ lengths between points. So there’s no need to specify with such notation . If it was on the complex plane hypothetically, I think use of the moduli signs would be better suited in that sense

 

[Dzeeshr]

Here’s a weird question I got in an exam, it asked to Find the complex number represented by OB and AC , yet above the OB and the AC my teacher used just a straight line, like what you use for the conjugate . OABC was a rhombus. I just assumed she made a mistake and meant to put an arrow, yet apparently this is valid notation ? I don’t know, a lot of the class thought it was conjugate and did a lot of extra working out and got it wrong . So can you write a complex number like that? Without it denoting conjugate? I guess it implies if you have a vector OB, and you want to write the conjugate you can’t ? Unless you change the form to another way of notation like with the tilde.

 

[Jaros]

You don’t need this when the question is obviously not dealing with vectors, but distances/ lengths between points. So there’s no need to specify with such notation . If it was on the complex plane hypothetically, I think use of the moduli signs would be better suited in that sense

no u needed that so u can use the distance formula, see the solution I posted above

 

[Dzeeshr]

no u needed that so u can use the distance formula, see the solution I posted above

Eh. Maybe. Still means the same thing.

 

[tywebb]

any help? ik its easy but tm brain is fried

 

[ineed99atar]

here working out:
View attachment 52137
U go to ngo and sons aswell, peak recognises peak

wait where did x+1 go?

 

[CirrusTheJet]

Thank you Jaros.

 

[Jaros]

wait where did x+1 go?

I expanded the RHS expression