BionicMango
Active Member
- Joined
- Oct 22, 2025
- Messages
- 239
- Gender
- Male
- HSC
- 2024
OH right because the value of A is clearly just a real number which means that any definite integral will be a constant multiple of A since that's how real numbers work (as long as all terms are made up of either constants or the dummy variable). If anything the e^(-m) term is the closest thing to a 'variable' so the integral can't be written like kA. So either most of the familiar functions' definite integrals will work or none of them will.
Method 1 is my favourite of course




