mreditor16
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You've shown that cg = hb. Since this must be true for ALL real choices of g and h, c must equal b, and both must be 0.
You mean we're trying to show a and d are equal, whilst b = c = 0?You've shown that cg = hb. Since this must be true for ALL real choices of g and h, c must equal b.
Now use this fact in the other equalities you can derive. You should end up being able to show that a, b, c and d are all equal, which is what we're aiming to show.
Yep, sorry. (b = c = 0 and a = d)You mean we're trying to show a and d are equal, whilst b=d=0?
How does this work?Wait, I don't get one part....
Why can't g=h=0?You've shown that cg = hb. Since this must be true for ALL real choices of g and h, c must equal b, and both must be 0.
Since we are told that AX = XA for any choice of X, we must have cg = hb for any choice of g and h. g and h are free for us to choose (as we can let X be anything) and the equality must always be maintained. In order for this equality to be maintained for all choices of g and h (hence including non-zero choices), we need c = b = 0.How does this work?
Why can't g=h=0?