The lower the resistance the more the eddy currents though.
But doesn't higher resistance result in more heat generated?
But is it faster heat?
Well the answers says yes but I can't explain it.
If the metal has high resistance then less eddy currents will flow through it.
common sense m8, name a saucepan made of high resistance material (i.e. rubber, plastic.. etc).. exactly they are non-existent
this.
Yep, that makes sense . Thanks !:$\\\\(1)~V=IR$ and $(2)~P(loss)=I^{2}R\\\\$Now, assuming voltage is constant, if we decrease resistance, current in (1) would increase. Looking at (2), power loss (i.e heat dissipation) is proportional to the square of the current, so in order to increase power loss its more beneficial to increase current as its effect on power loss is much higher. $\\\\$So the net effect of increasing resistance is increasing heat, as it causes an increase in current, and $P(loss)=I^{2}R$.\\\\Think about it, using these equation, assume voltage is 20, current is 4 and resistance is 5. With this information, power loss is 80. Now reduce resistance by 1, thus increasing current by 1. Now power loss is 100.$)
