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Minor segment (1 Viewer)

atakach99

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find the area of the minor segment correct ot 2 decimal places, given

radius is 7.2 mm and the angle subtended is 55 degrees
 

atakach99

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yea thats what i do...but when i calculate it i get a different answer to the one in the back of the book... the answer in the back is 3.65 mm squared

when u calculate it.....is ur calculator in Rad mode or Deg mode
 

lyounamu

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atakach99 said:
yea thats what i do...but when i calculate it i get a different answer to the one in the back of the book... the answer in the back is 3.65 mm squared

when u calculate it.....is ur calculator in Rad mode or Deg mode
Radian mode.
 

conics2008

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atakach99 put your cal on rad mode not DEG because those types of question need to be in radians =)
 

lyounamu

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Solution is the followings:

55 degrees = 55 degrees/ 180 degrees x pi
= 11/36 . pi
Now,

Area of the minor segment = 1/2 . r^2 (11pi/36 - sin (11pi/36))
= 1/2 . 7.2^2 (11pi/36 - sin (11pi/36))
= 3.64899282...
= 3.65 mm^2 (to nearest 2 decimal places).
 

lyounamu

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aMUSEd1977 said:
Well done on posting the exact same thing i did without the final answer.


Also, sup tags are the greatest thing ever.

Try them.
'sup tags'??? Being sarcastic???
 

lyounamu

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aMUSEd1977 said:
Yes.

x{sup}2{/sup} will give x2.

Change {} to []

It's so much easier to read than having ^n's everywhere
Okay. I have never seen one before but I will start using it.

EDIT: I did not see your solution.
 
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