Mod 5 ice table (1 Viewer)

[Average Boreduser]

for this qn, why do we take keq=[c}/AB?
because we have C initially added, wouldnt this render the reactants the products and therefore keq is the reciprocal of the forward rxn?
I'm confused bc I don't see why we'd take C as the products here

 

[saltedparsley]

from what i can gather, they want the Keq for the reaction as written (i.e. forward reaction), so yes Keq = [C]^2/[A_2] as this is the actual formula for Keq.
if you started off with C, you'd essentially flip the reaction so then Keq for that reverse reaction would be the reciprocal, but only for that reverse reaction (i.e. for 2C <--> A_2 + B)
so since the reaction they give you is the forward reaction and they want the Keq for that, you'd treat C as the product since it's the product in the forward reaction.
essentially what you could do is find the Keq of the reverse reaction using C as the reactant with the info given, then take the reciprocal of that, which would give you Keq of the forward reaction as written.
hopefully this makes some sense.

 

[Average Boreduser]

from what i can gather, they want the Keq for the reaction as written (i.e. forward reaction), so yes Keq = [C]^2/[A_2] as this is the actual formula for Keq.
if you started off with C, you'd essentially flip the reaction so then Keq for that reverse reaction would be the reciprocal, but only for that reverse reaction (i.e. for 2C <--> A_2 + B)
so since the reaction they give you is the forward reaction and they want the Keq for that, you'd treat C as the product since it's the product in the forward reaction.
essentially what you could do is find the Keq of the reverse reaction using C as the reactant with the info given, then take the reciprocal of that, which would give you Keq of the forward reaction as written.
hopefully this makes some sense.

ahhh so if they didnt give me the eqn, I can assume the C is a reactant or lhs of the eqn so keq=AB/C?

 

[saltedparsley]

nah i don't think they'd ever not give eqn for a question like this, you need mole ratios and stuff to find Keq

 

[kkk579]

nah i don't think they'd ever not give eqn for a question like this, you need mole ratios and stuff to find Keq

cant one be established?

 

[Average Boreduser]

nah i don't think they'd ever not give eqn for a question like this, you need mole ratios and stuff to find Keq

I mean, u could prolly just be given the two chemicals and u kinda can work w it from there since u can balance it and somewhat determine what products are produced etc.

 

[saltedparsley]

yeah, that'd be if they gave you the actual names/formulas of the chemicals tho. otherwise i don't see how you'd figure it out with no formula or ratios and arbitrary species like a, b, c etc.

 

[Average Boreduser]

alr alr i understand now tysm

 

[Average Boreduser]

cant one be established?