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Moles q (1 Viewer)
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Use the Avogadro's Law
n = no. of particles / 6.022 x 10^23
that 6.022 x 10^23 is Avogadro's number and is found on the data sheet
By combining that formula with n = m / MM, you can solve both of those questions
1) n = m / MM
n = 0.213 / 32.07
n = 0.00664... moles
n = no. of particles / 6.022 x 10^23
0.00664... = no. of particles / 6.022 x 10^23
no. of particles = 3.999644.... x 10^21
Use the same formulas for question 2 and you will get the answer
n = no. of particles / 6.022 x 10^23
that 6.022 x 10^23 is Avogadro's number and is found on the data sheet
By combining that formula with n = m / MM, you can solve both of those questions
1) n = m / MM
n = 0.213 / 32.07
n = 0.00664... moles
n = no. of particles / 6.022 x 10^23
0.00664... = no. of particles / 6.022 x 10^23
no. of particles = 3.999644.... x 10^21
Use the same formulas for question 2 and you will get the answer
Last edited:
Use n = m/MM to find a
formula of aluminium chloride is AlCl3
n(Al) = n(AlCl3)
since each aluminium chloride has 1 Al
n(Cl) = 3xn(AlCl3)
since each aluminium chloride has 3 Cl