# Moments Question (1 Viewer)

#### mandog97

##### Member

Could somebody please show me their working out for this. I'm stumped
thanks

#### D94

##### New Member
What you can do is split the force into vertical and horizontal components. The vertical component is 200sin(30) (down) and the horizontal component is 200cos(30) (left).

As with all moments, the sum of moments is the the sum of (Force x Perpendicular Distance), so the vertical force acts downwards and is 50mm from the pivot, and the horizontal force acts leftwards and is 150mm from the pivot.

The answer is 21 Nm.

#### astroman

##### Well-Known Member
Sum of positive moments clockwise (pivot) = -(200cos30 x 0.15) + (200sin30 x 0.05)
= -20.98Nm
= 21NM
A

Last edited:

#### keepLooking

##### Active Member
If you still do not understand what they did, they took moments around the Pivot.

#### mandog97

##### Member
Yep fully understand. Thanks guys!!

#### Apdo

##### New Member
Yeah I got the question wrong first because I thought I was calculating an unknown force, but it's just summing that force around the fulcrum