swagswagyoloswag
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- 2015
The acceleration of a particle is 2x-5 m/s^(2) where x is the distance in metres from the origin.
a) Find expression for the velocity of this particle in terms of x, given that the particle is at rest one metre to the left of the origin initially.
I got v^2 = 2x^2 - 10x -12 but can't find a condition to just find v. Also, when I let v = 0, it shows that it stops at two positions, x = -1 and x = 6.
But since it starts at rest at x = -1, a = 2(-1)-5 = -7 initially, wouldn't it mean it only travels left because v = 0, a<0 ?
a) Find expression for the velocity of this particle in terms of x, given that the particle is at rest one metre to the left of the origin initially.
I got v^2 = 2x^2 - 10x -12 but can't find a condition to just find v. Also, when I let v = 0, it shows that it stops at two positions, x = -1 and x = 6.
But since it starts at rest at x = -1, a = 2(-1)-5 = -7 initially, wouldn't it mean it only travels left because v = 0, a<0 ?