Multiple choice-Q14 (1 Viewer)

[Aaron.Judd]

Aaron Judd that's bs
I know Mrs Pooviah and she aint that dumb

Exactly, she's super smart. Hence it is C.

 

[dp624]

Exactly, she's super smart. Hence it is C.

I don;'t f*cking think so you troll. Retard i go to JRAHS and you certainly don't

 

[Shedow]

I approve of dp624.

 

[eli16]

the answer is b full stop

 

[Mark576]

yeah I put (b). the question is pretty standard

 

[Aaron.Judd]

The answer is C. d9684 pm me, tell me who you are and if I like you I'll reveal my identity proving I do (or did) go to JRAHS.

 

[iEdd]

Yes, we already know that you think that there is no such thing as diluting acids. You think the answer is C, because you believe if I put one drop of HCl in a pool, the pH of the whole pool will be 1. Actually, let's make a similar actual question:

100mL of 1M HCl is added to a 50 000L swimming pool. What is the pH of the final solution?

b) pH=5.7, as H⁺ concentration was calculated in 50L
c) pH=1, as there were that many H⁺ ions in the original 100mL

Let me guess, Mrs Pooviah says it's C?

 

[dp624]

The answer is C. d9684 pm me, tell me who you are and if I like you I'll reveal my identity proving I do (or did) go to JRAHS.

PM'ed

 

[drobby]

n(H+ in HCl)= 0.02 x 0.08 = 1.6x10^-3

n(OH- in NaOH)= 0.03 x 0.05 = 1.5x10^-3

That is right

But 0.0016 - 0.0015 is 0.0001

This is number of moles of H+ ions left in the solutions

Ph = -log10[H+]

c = n/v

volume is 20mls +30 mls = 0.05 L

therefore [H+] is 0.0001/0.05 = 0.002

Ph = -log10[0.002] is equal to 2.69... = 2.7

did the same and got c

 

[iEdd]

You forgot to divide by .050L

 

[eddy11]

its C, i initially put B but its painfully obvious its C having realised that i forgot to caculate the [H+] and rather just the number of moles of H+ ions.

 

[iEdd]

Um, swap where you said B and C.

C is what you put if you forget to find concentration.

 

[nswchu123]

It's B.

Pls refer to Kearnzo's calculation.
pH = - log [H+]