~ ReNcH ~
!<-- ?(°«°)? -->!
I think I got that one right...Dxrtzx said:
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multiple choice...WTF? (1 Viewer)
- Thread starter daffidoll
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sausage roll
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Did anyone find the heat of combustion question hard? I picked B
falltopieces
Member
I picked B as well.sausage roll said:
Um...how about the AAS question. Which one is the right answer?
falltopieces
Member
glad got that one correctxrtzx said:
Ethyl pentanoate is used as food flavouring right?
Captain Gh3y
Rhinorhondothackasaurus
Me too, then.serge said:
*hi five*
laserbrainz
New Member
yeah, I think the ester (Ethyl pentanoate) is pineapple flavouring, but not certain on that. It is a flavour though (took back my textbook). Any of you 100% MC'ers know?
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falltopieces
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yup i guess it's the pineapple flavouringlaserbrainz said:
justchillin
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I know 1 is B...but the defonition of an atom is something neutral isnt it...so D is also correct, if they had said "ion" then yes wrong, but they said atom...hence number of protons = number of electrons. ie excess of electrons = unbalanced ration neutronsrotons, ie radioactive. Someone pro ve me wrong...though I know its not the most correct.,..haha
rotons, ie radioactive. Someone pro ve me wrong...though I know its not the most correct.,..haha
~ ReNcH ~
!<-- ?(°«°)? -->!
That reasononing is what made me consider D, but B still seems more correct even though it's not strictly "correct". Meh, I just have my fingers crossed that BOS also thinks the answer is B.justchillin said:I know 1 is B...but the defonition of an atom is something neutral isnt it...so D is also correct, if they had said "ion" then yes wrong, but they said atom...hence number of protons = number of electrons. ie excess of electrons = unbalanced ration neutrons
~ ReNcH ~
!<-- ?(°«°)? -->!
lol...14/15 for me then. Damn my stupidity for Q5Captain Gh3y said:
punki_pixi
New Member
For 1 i had B. I was going to put D because it said isotope and that has different number of neutrons than the normal atom doesnt it? and I was thinking the number of electrons equals number of protons. But it could be an ion couldn't it? Well it also said what condition produces... and if there are too many protons and neutrons this would produce an isotope through decay, so I ended up with B.
I had H2So4 for the buffer thing since its diprotic... the CH3COOH can only lose its end hydrogen atom can't it? I'm just hoping its right but if not oh well...
I had H2So4 for the buffer thing since its diprotic... the CH3COOH can only lose its end hydrogen atom can't it? I'm just hoping its right but if not oh well...
~ ReNcH ~
!<-- ?(°«°)? -->!
That buffer one:punki_pixi said:
http://www.ncbi.nlm.nih.gov/entrez/query.fcgi?cmd=Retrieve&db=PubMed&list_uids=9462046&dopt=Abstract
Just a random Google search brought this up, so I'm guessing D is correct, whether or not the others are correct or incorrect.
yeh.. this is how i approached the question..
*buffers comprise of a weak acid and its conjugate base, so there goes A and C
*B is wrong cuz it isn't even the conjugate
*thus the answer is D
buffers dun hav to be diprotic
*buffers comprise of a weak acid and its conjugate base, so there goes A and C
*B is wrong cuz it isn't even the conjugate
*thus the answer is D
buffers dun hav to be diprotic
Captain Gh3y
Rhinorhondothackasaurus
D is correct because:~ ReNcH ~ said:
HCl is a strong acid, therefore its conjugate is an extremely weak base, too weak to actually act as a base.
H2SO4/HSO4 are an acid/base conjugate pair, but HSO4 is amphiprotic and is not guaranteed to act as a base.
H2PO4/PO4 are not a conjugate acid/base pair,
so that leaves only acetic acid/acetate ions, and of the 3 conjugate pairs, acetate ions are easily the strongest base.