Multiple Choice (1 Viewer)

Rafy

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Share your MC Answers here
 

mattard94

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1.C
2.B
3.C
4.C
5.D
6.C
7.C
8.A
9.B
10.D
11.D
12.A
13.A
14.C
15.C
16.D
17.C
18.B
19.D
20. I put C but I think it's D
 

Fizzy_Cyst

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1.c
2.b
3.b
4.c
5.b
6.c
7.c
8.a
9.b
10.d
11.d
12.a
13.a
14.a
15.c
16.b
17.b
18.b
19.d
20.d
 

Wight

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These are from memory so :S
1. C
2. B
3. B (I'm probably wrong here)
4. C
5. B
6. C
7. C (had to re calculate this one...couldnt remember it (i think i got it wrong in the exam LOL...can't use a calculator))
8. A
9. B
10. D
11. D
12. A
13. A
14. A
15. C
16. C
17. B
18. B
19. A (LOL SHIT IM A RETARD..it's D)
20. D
 
Last edited:

Patato

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im a little confused about the question with the pendulum and that split-ring thing.

Does EMF get induced into ring that isn't closed? I thought it did, but I've heard that it doesn't, hence the answer was the constant zero emf graph?
 

K4M1N3

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I was so put off by the first 10 questions being all b's and c's only
 

damo_g

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These are from memory so :S
1. C
2. B
3. B (I'm probably wrong here)
4. C
5. B
6. C
7. C (had to re calculate this one...couldnt remember it (i think i got it wrong LOL...can't use a calculator))
8. A
9. B
10. D
11. D
12. A
13. A
14. A
15. C
16. C
17. B
18. B
19. A (LOL SHIT IM A RETARD..it's D)
20. D
Mine look fairly similar with a couple different. Unlucky on question 19, i put C at first and quickly realised my mistake thank fuck haha. Pretty sure your number 7 is right, unless i can't use a calculator either.
 

Wight

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Mine look fairly similar with a couple different. Unlucky on question 19, i put C at first and quickly realised my mistake thank fuck haha. Pretty sure your number 7 is right, unless i can't use a calculator either.
That number 7 is...but the one I put in the exam...I don't think it was that (can't remember...oh well)
 
K

kleenextissues1

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20 is A.

W is proportional to F (W=fs)

so half of init. grav. potential energy is half init. force.
If grav Ep is halved, then radius is doubled... So according to F = Gm1m2/d^2 , Grav force is quartered... Hence answer is D
 

69mitch9

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Hey, i'm pretty sure the answer to Question 9 is A. It's a trick question because the spacecraft isn't moving away or towards the observer so Length Contraction doesn't occur.
 
K

kleenextissues1

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hey, i'm pretty sure the answer to Question 9 is A. It's a trick question because the spacecraft isn't moving away or towards the observer so Length Contraction doesn't occer.
Doesn't it contract in the direction of motion? (meaning answer is B)
 

Urgh

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Hey, i'm pretty sure the answer to Question 9 is A. It's a trick question because the spacecraft isn't moving away or towards the observer so Length Contraction doesn't occur.
observer across the street can see length contraction...
 

slavdaddy

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1. C
2. B
3. B
4. C
5. B
6. C
7. C
8. A
9. B
10. B ( isnt d incorrect? Because it changes dependant on the current? Ie the current is the thing u change? Correct me if im wrong)
11. D
12. D
13. A
14. A
15. C
16. B
17. B
18. B
19. D
20. D
 

Urgh

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with 14 would there be eddy currents generated? cause i assumed the split meant no induced current so did D :S
 

Urgh

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1. C
2. B
3. B
4. C
5. B
6. C
7. C
8. A
9. B
10. B ( isnt d incorrect? Because it changes dependant on the current? Ie the current is the thing u change? Correct me if im wrong)
11. D
12. D
13. A
14. A
15. C
16. B
17. B
18. B
19. D
20. D
"rod a was placed at different distances from rod b". its distance between
 

CalumGemmell

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Hey, i'm pretty sure the answer to Question 9 is A. It's a trick question because the spacecraft isn't moving away or towards the observer so Length Contraction doesn't occur.
It's not a trick question, it moves relative to the observer, who is across the street. It's B
 

slavdaddy

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"rod a was placed at different distances from rod b". its distance between
Its a repulsive force between the two rods because tey have a cureent in different directions. Hence the distance of the ro depends on the current that glows through them?
 

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