Natural Growth/Decay (1 Viewer)

[khorne]

Check my Induction, sexy beasts

Go to my next post:

Q: http://imageshack.us/photo/my-images/193/question1w.png/

Just the first part:
if i prove the first part, that is 0.8DT1/dt + dT2/dt = 0, can I just say that rate of change of (0.8t1 + t2) = 0, thus it implies that if neither temperature is changing then the temperature would simply be 0.8t1 + t2 = 756

It works, but idk how I would explain it?

Edit: I guess I could say d/dt(0.8t1 + t2) = 0, is a maximum, which occurs at t1 = 900, t2 = 36?

 

[Drongoski]

@ t=0, T₁ = 900 and T₂ = 36






ii)







When t = 0, T₁ = 900

 

[Drongoski]

iii)






(nearest degree)



Edit

1) Where does this question come from?

2) Sheilla on your sig sure looks like Miss Piggy.

 

[khorne]

Yeah, thanks for the part. I needed to argue that my wording of the explanation was correct for an exam. I think the question originally came out of a James Ruse trial for 4U, 2009 or 2008 I think. If you need it, I can find/upload the paper.

The girl in my sig is also MissMinx, the biggest camwhore on the net. Highly recommend.