# Need help with a question. (1 Viewer)

#### Bongo

##### New Member
Find the area enclosed between the curve y = x^3 , the x -axis and the line y = -3 x + 4.

I've tried everything but I can't seem to find the answer. Any help will be greatly appreciated

#### integral95

##### Well-Known Member
Yeah that's because this not your straight forward "top minus bottom" kind of question.

First you should draw out the curves, then find the point of intersection (which is x = 1 by inspection)

The area given above is

$\bg_white \int_0^1 \ x^3 \ \ dx + \int_1^{\frac{4}{3}} \ \ -3x + 4 \ \ dx = \frac{5}{12}$