This. AND make sure you test if it is a maximum, remember a parabola could have a max or minMax height when dh/dt = 0. This is why at the highest point looks the path like the vertex of a parabola.
So make dh/dt = 0 and find the time it takes to reach the highest point, then subbing it back into h.
Yeap!Max height when dh/dt = 0. This is why at the highest point the path looks like the vertex of a parabola.
So make dh/dt = 0 and find the time it takes to reach the highest point, then subbing it back into h.
I thought when you make the velocity = 0 thats when it rests.Max height when dh/dt = 0. This is why at the highest point the path looks like the vertex of a parabola.
So make dh/dt = 0 and find the time it takes to reach the highest point, then subbing it back into h.
It also means max distance, same with max velocity when a=0I thought when you make the velocity = 0 thats when it rests.
In both cases, there should be a 'possible' in there.It also means max distance, same with max velocity when a=0
do you know how i can find how far the projectile will travel in the first 4 seconds?It also means max distance, same with max velocity when a=0