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Need help with this Q! (1 Viewer)
- Thread starter mkv_86
- Start date
Fizzy_Cyst
Owner @ Sigma Science + Phys Goat
Seeing as the plane of the coil is perpendicular to the magnetic field, there will be no torque. T = nBIACos(@), in this case @ = 90 therefore T = 0.
The forces on the sides of the coil will not force rotation of the coil (force on the top side is up and bottom side is down), rather they will try and stretch the coil.
As for (c), the coil will remain stationary (perhaps experience a little stretching in the +/- y direction due to the forces. The justification is that torque = 0, therefore angular/rotational motion will not change.