Neutralisation question (1 Viewer)

[bEAbEA]

Can anyone help me with these two questions before my half yearly?

A bottle of vinegar is labelled 4.0% w/v (4.0g per 100mL of solution) acetic acid (ethanoic acid)

a) Describe the laboratory procedure you would use to verify this procedure. (3)
b) Calculate te volume of 0.118mol/L NaOH required to neutralise the acid in 5.0mL of this vinegar

I'm having more trouble with part b, but any help would be appreciated.

Ta.

 

[[]

I think I can Help!

Привет!
Я - Год 12 заговорщиков Химии! Вы встретили моего друга,]? Он находится в на революции.
Надежда я была полезна.
Удача от [.

Sorry; it has been a really slow Chemistry lesson!

 

[Will Hunting]

4.0g per 100.0mL
So, 0.2g per 5.0mL

moles in acid sample: n = m/mm = 0.2/60 = 3.33 x 10^-3
Since mole ratio of titration reaction 1:1, moles of NaOH: n = 3.33 x 10^-3

Volume of NaOH needed: v = (3.33 x 10^-3)/.118 = 0.02797L (4 sig. figs.) = 27.97mL

 

[Dreamerish*~]

4.0g per 100.0mL
So, 0.2g per 5.0mL

moles in acid sample: n = m/mm = 0.2/60 = 3.33 x 10^-3
Since mole ratio of titration reaction 1:1, moles of NaOH: n = 3.33 x 10^-3

Volume of NaOH needed: v = (3.33 x 10^-3)/.118 = 0.02797L (4 sig. figs.) = 27.97mL

i have a thing with superscript

CH₃COOH_(aq) + NaOH_(aq) --> NaCH₃COO_(aq) + H₂O_(l)

ratio of CH₃COOH and NaOH = 1:1
CH₃COOH: 3.33 x 10^-3 mol
therefore: NaOH: 3.33 x 10^-3 mol = 27.97mL

 

[Will Hunting]

Yeah, I know, I'm so jealous! How do you pull that tricky sh*t!?

 

[bEAbEA]

Thanks, that was a great help!

 

[Dreamerish*~]

i don't know how to tell you without turning everything into subscript... = /

subscript: put "sub" into square brackets - i.e. [ ] and then write whatever you want to be subscripted. when you finish writing add "/sub" in square brackets [ ]

superscript: same thing, but with "sup"

 

[Will Hunting]

My most gracious and humble thanks go out to you... I am eternally in your debt... lol

 

[dead]

j_us^t had to try the s_ubs^cript.

hope it worked